WebTags for GCD - Greatest Common Divisor using Functions in C. sample hcf; sample gcd; greatest common divisor program using fucntions; find gcd in c; finding hcf; highest common factor; c program to find gcd of two numbers; c; c program for gcd using function; c program to find gcd of three numbers using function; c program to find gcd … WebApr 21, 2024 · C Program to Find Greater Number by Using Function. Tuts April 21, 2024. 778 1 minute read. Write a c program that takes integer input a, b, c, d, e, f; and make …
Cpp program:find greatest of three numbers using function
WebNov 9, 2024 · C Program To Find Largest Of N Numbers Using While Loop #include int main(void) { int n; int max = 0; printf("Enter a number (0 to exit): "); scanf("%d", &n); while (n != 0) { if (max < n) { max = n; } printf("Enter a number (0 to exit): "); scanf("%d", &n); } printf("Max is: %d", max); } Output: WebSep 15, 2024 · Our task is to create a Program to Find the Largest Number using Ternary Operator in C++. The elements can be − Two Numbers Three Numbers Four Numbers Code Description − Here, we are given some numbers (two or three or four). We need to find the maximum element out of these numbers using a ternary operator. bingwit 2022 cast
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WebJan 5, 2016 · I made a small program which prints the largest and smallest integers among the four input numbers. Is there any shortest way using the basic c programming methods? #include main () { int a, b, c, d, y; printf ("Enter four integers (separate them with spaces): "); scanf ("%d %d %d %d", &a, &b, &c, &d); if (a>b && a>c && a>d) { if (b WebOct 17, 2024 · import math def maximumoffour (i,j,k,l): m=max (i,j,k,l) print ("Maximum of the given four numbers",i,j,k,l, "is",m) i=eval (input ("enter the value 1 :")) j=eval (input ("enter the value 2 :")) k=eval (input ("enter the value 3 :")) l=eval (input ("enter the value 4 :")) maximumoffour (i,j,k,l) Share Follow edited Oct 17, 2024 at 16:36 Web#include using namespace std; int main() { double n1, n2, n3; cout > n1 >> n2 >> n3; // check if n1 is the largest number if(n1 >= n2 && n1 >= n3) cout = n1 && n2 >= n3) cout << "Largest number: " << n2; // if neither n1 nor n2 are the largest, n3 is the largest else cout << "Largest number: " << n3; return 0; } … bingwit full movie