WebJun 9, 2024 · Write three terms of g.p a=81,r=-1/3 Advertisement phani67 is waiting for your help. Add your answer and earn points. Answer 6 people found it helpful JennyGoud Step … Weba3-8b3 Final result : (a - 2b) • (a2 + 2ab + 4b2) Step by step solution : Step 1 :Equation at the end of step 1 : (a3) - 23b3 Step 2 :Trying to factor as a Difference of Cubes: 2.1 ... a3 −b3 = …
if (a+1/a) 2 = 3, then (a3 + 1/a3)=? - NextGurukul
WebJul 19, 2016 · First term: a 1 = 4. Second term: a 2 = a 1 r = 4 (3) = 12. Third term: a 3 = a 1 r 2 or just a 2 r = = 12 (3), etc. in a Geometric sequence, you simply multiply the most recent … WebMar 19, 2024 · a1 = 2 an+1 = (an)^2 + 5 a2 = (a1)^2 + 5 - 2^2 + 5 = 9 a3 = (a2)^2 + 5 = 9^2 + 5 = 81+5 = 86 a3 = 86 Upvote • 0 Downvote Add comment Report Still looking for help? Get the right answer, fast. Ask a question for free Get a free answer to a quick problem. Most questions answered within 4 hours. OR Find an Online Tutor Now florid diabetic koilocytosis
write 3 terms of GP when a=81,r=-1/3 - Brainly.in
WebThe correct option is C ±198It is given thata2+ 1 a2=34Using identity we have(a+ 1 a)2 = a2+ 1 a2+2⇒ (a+ 1 a)2 = 34+2⇒ (a+ 1 a)2 = 36⇒ (a+ 1 a)2 = 62⇒ (a+ 1 a) =±6Now, again from cubic identity we have,a3+ 1 a3=(a+ 1 a)3−3(a)(1 a)(a+ 1 a)Case I: When (a+ 1 a) = +6,a3+ 1 a3=63−3(a)(1 a)6⇒ a3+ 1 a3=63−(3)(6)⇒ a3+ 1 a3=216−18 ... WebThe formula for the nth term of a geometric progression whose first term is a and common ratio is r is: a n =ar n-1. The sum of n terms in GP whose first term is a and the common ratio is r can be calculated using the formula: S n = [a (1-r n )] / (1-r). The sum of infinite GP formula is given as: S n = a/ (1-r) where r <1. ☛ Related Topics: WebGiven that, the fourth term in geometric sequence is a 4 = 81 and the common ratio is r = − 3. Recall that, the general term of the geometric sequence is a n = a r n − 1 . Here, a is the … great wolf lodge manteca hiring